[WrestleFuck]

Obviously this fight couldn't happen in real life due to their difference in weight classes, thankfully it can happen here! Would Ronda prove that size really does matter by destroying the "Karate Hottie" in a lopsided beatdown? Or would Waterson overcome the odds to chop down the giant? You decide!


Michelle "Karate Hottie" Waterson

Height: 5'3"
Weight: 115 lbs (strawweight)







"Rowdy" Ronda Rousey

Height: 5'7"
Weight: 135 lbs (bantamweight)

[HumiliationOne]

Yes. The Karate Hottie turns Ronda into her personal punching bag. Rowdy is made into laughing stock getting smacked around.

[DogWithABone]

Rousey walks around at 160+. She fought at 154 in judo. Waterson was the 105 champ for Invicta. You're talking about a 40 pound weight advantage against someone who, despite her nickname, is a ground fighter as well. Rousey squashes the significantly hotter Waterson.

[WildAtHeart]

Michelle is the hottest fighter in UFC and Ronda's confidence is shot.  A ring girl might beat her now!

[HumiliationOne]

Michelle is the hottest fighter in UFC and Ronda's confidence is shot.  A ring girl might beat her now!

Yea, wasn't she talking shit about Arianna a while back? After asswhoopings she has taken she better watch that big mouth. 

[herboyfriend]

I don't find Michelle sexy. Ronda is so sexy though, and also she'd beat the hell out of Michelle.

[Ginny38]

Rousey walks around at 160+. She fought at 154 in judo. Waterson was the 105 champ for Invicta. You're talking about a 40 pound weight advantage against someone who, despite her nickname, is a ground fighter as well. Rousey squashes the significantly hotter Waterson.

Damm! I wish I'd said that.

I can't think of one reason why Rousey couldn't beat a woman so much smaller when she's beaten other fighters her own size. The fact that Waterson isn't known as a puncher is just one more reason why this is ("a clown question, bro" as someone once said).